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  • leetcode-test
  • 7-reverse.js
  • lintry's avatar
    已完成的答案 · f21637e1
    f21637e1
    lintry authored 2019-06-18 14:23:17 +0800
7-reverse.js 326 Bytes
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/**
 * @param {number} x
 * @return {number}
 */
var reverse = function(x) {
    let r;
    let sign = Math.sign(x);
    try {
        r = Number.parseInt(String(Math.abs(x)).split('').reverse().join('')||'0');
    } catch (e) {
        r = 0;
    }
    return r > Math.pow(2, 31)-1 ? 0 : sign*r;
};

console.info(reverse(0));